SQL实战91.获得积分最多的人(三)
2021/4/15 2:25:38
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题目
解答
with tmp as ( select a.user_id, a.cnt as add_num ,if(b.cnt is null,0,b.cnt) as reduce_num from (select user_id,sum(grade_num) as cnt from grade_info where type = "add" group by user_id ) a left join (select user_id,sum(grade_num) as cnt from grade_info where type = "reduce" group by user_id ) b on a.user_id = b.user_id ) select c.user_id as id,u.name,c.grade_num from (select t.user_id,t.grade_num,rank() over (order by t.grade_num desc) as ranking from (select user_id,(add_num-reduce_num) as grade_num from tmp ) t ) c left join user as u on c.user_id = u.id where c.ranking = 1 order by c.user_id;
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