python实现删除链表倒数第n个节点
2021/7/12 20:07:53
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# 删除链表倒数第n个节点。假设n大于0 def remove_nth_from_end(head): fast = head count = 0 while fast and count < n: fast = fast._next count += 1 if not fast and count < n: # not that many nodes return head if not fast and count == n: return head._next slow = head while fast._next: fast, slow = fast._next, slow._next slow._next = slow._next._next return head
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