mysql获取当月数据_MySQL中获取天、周、月等数据

2022/1/13 2:06:04

本文主要是介绍mysql获取当月数据_MySQL中获取天、周、月等数据,对大家解决编程问题具有一定的参考价值,需要的程序猿们随着小编来一起学习吧!

MySQL中获取天、周、月等数据

1.今天

select * from 表名 where to_days(时间字段名) = to_days(now());

2.昨天

SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1

3.近7天

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)

4.近30天

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名)

5.本月

SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' )

6.上一月

SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 时间字段名, '%Y%m' ) ) =1

7.查询本季度数据

select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());

8.查询上季度数据

select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));

9.查询本年数据

select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());

10.查询上年数据

select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));

11.查询当前这周的数据

SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());

查询本周所有的数据(本周第一天是周一)

SELECT * FROM task WHERE YEARWEEK(date_format(时间字段,'%Y-%m-%d'),1) = YEARWEEK(now(),1);

查询本周所有的数据(本周第一天是周日)

SELECT * FROM task WHERE YEARWEEK(date_format(时间字段,'%Y-%m-%d')) = YEARWEEK(now());

12.查询上周的数据

SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;

13.查询上个月的数据

select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')

select * from user where DATE_FORMAT(pudate,'%Y%m') = DATE_FORMAT(CURDATE(),'%Y%m') ;

select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())

select * from user where MONTH(FROM_UNIXTIME(pudate,'%y-%m-%d')) = MONTH(now())

select * from user where YEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = YEAR(now()) and MONTH(FROM_UNIXTIME(pudate,'%y-%m-%d')) = MONTH(now())

select * from user where pudate between 上月最后一天 and 下月第一天

14.查询当前月份的数据

select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')

15.查询距离当前现在6个月的数据

select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();

select curdate(); --获取当前日期

select last_day(curdate()); --获取当月最后一天。

select DATE_ADD(curdate(),interval -day(curdate())+1 day); --获取本月第一天

select date_add(curdate()-day(curdate())+1,interval 1 month); -- 获取下个月的第一天

select DATEDIFF(date_add(curdate()-day(curdate())+1,interval 1 month ),DATE_ADD(curdate(),interval -day(curdate())+1 day)) from dual; --获取当前月的天数
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版权声明:本文为CSDN博主「Atlas-Geo」的原创文章,遵循CC 4.0 BY-SA版权协议,转载请附上原文出处链接及本声明。
原文链接:https://blog.csdn.net/weixin_34024555/article/details/112841642



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