【1.8】shell读入参，shell用户交互式输入

本文主要是介绍【1.8】shell读入参，shell用户交互式输入，对大家解决编程问题具有一定的参考价值，需要的程序猿们随着小编来一起学习吧！

代码：

#!/bin/bash

set -e

if [ $# -ne 3 ]
then
    echo "[error] please input three digits, usage: create_database.sh <segno> <start> <end>"
    exit 1
fi

seg=$1; start=$2; end=$3

printf "将在国内库中加区[%s%04d-%s%04d], 是否继续? [y/n]:" $seg $start $seg $end
read countinue
if [ "x$countinue" != "xy" ]
then
    exit 0
fi

mysqldump  -urwuser -pQBhhvX2Fi2QnEurA  -h10.154.28.249  --set-gtid-purged=OFF  --default-character-set=utf8 --add-drop-table=false --no-data g
ame_70_0001 >init.sql
version=`mysql  -urwuser  -pQBhhvX2Fi2QnEurA  -h10.154.28.249  -D game_70_0001 -Bse "select version from db_version"`
logic_version=`mysql  -urwuser  -pQBhhvX2Fi2QnEurA  -h10.154.28.249  -D game_70_0001 -Bse "select config_value from global_config  where config
_key='LOGIC_VERSION'"`

for (( i=$start;i<=$end;i++ ))
do

    ch=$(printf "%04d" $i) 

    db1="game_${seg}_"
    sql1="create database $db1$ch;"
    db="$db1$ch"

    echo  $sql1

    mysql --default-character-set=utf8 -uroot -p123456    -e "$sql1"
    
    echo  "init table"
    mysql --default-character-set=utf8  -uroot -p123456 -D$db < init.sql
    
    sql2="use $db1$ch;insert into db_version values(1,'$version');insert into global_config(config_key,config_value) values('LOGIC_VERSION','$l
ogic_version')"
    echo $sql2
    mysql -uroot -p123456    -e "$sql2"
    
done
    
echo `date` "done--------------"

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